JEE Main Trigonometry Important Questions 2025: The National Testing Agency (NTA) has scheduled to conduct the Joint Entrance Examination – Main (JEE Main) examination from January 22 to 30, 2025. The JEE Main Trigonometry Important Questions 2025 are available here for the candidate's reference. Note that the provided questions have been taken after a thorough analysis of the two shifts on January 22, 23, and 24, 2025. On these three days, Trigonometry has been one of the most important topics throughout. Therefore, it is very important for the candidates to have conceptual clarity. Candidates can go through the JEE Main Trigonometry Important Questions 2025 below.
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JEE Main Trigonometry Important Questions 2025 Based on Jan 22, 23 and 24 Analysis
The JEE Main Trigonometry Important Questions 2025 Based on Jan 22, 23, and 24 Analysis is available below.
Question 1: f(x) = 16(sec⁻¹ x)² + (cosec⁻¹ x)². Then the difference between the maximum and the minimum value of f(x) is equal to: (Jan 22, Shift 1)
Answer: 1089 (1) 68π²
Question 2: If 2x² + (cos x) x - 1 = 0, where x ∈ [0, 2π], has roots α and β, then the maximum and minimum values of α² + β² are M and m. Then find 16(M + m). (Jan 22, Shift 2)
Answer: 25
Question 3: If x ∈ [0, 2] satisfies the system of equations 2sin²x = cos²x and cos²x = 3sin²x, then the sum of all real values of x is: (Jan 22, Shift 2)
Answer: π
Question 4: Let a and b be two unit vectors such that the angle between a and b is θ. If a + 36 and 2a + b are perpendicular to each other, then the product of all possible values of θ is? (Jan 22, Shift 2)
Question 5: Evaluate 4 - 1/2 * sqrt(5) lim (x-0) [cosecx (2cos^2 x + 3cos x) ^ (1/2) - (cos^2 x + sin x + 4) ^ (1/2)
Answer: - 1/2 * sqrt(5)
Question 6: If a and ẞ are real numbers such that sec^2 (arctan(alpha)) + co * sec(2) * (arccos(beta)) = 36 and alpha + beta = 8 then (alpha ^ 2 + beta) * i (a > β) (Jan 24, Shift 1)
Answer: 28
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