JEE Main Session 2 Modern Physics Previous Year Questions 2025
JEE Main Session 2 Modern Physics Previous Year Questions 2025 is given here for the interested students.
JEE Main Session 2 Modern Physics Previous Year Questions 2025: Modern Physics is one of the highest-scoring and most important subjects of JEE Main Session 2, and it includes high-end concepts such as the photoelectric effect, atomic structure, de Broglie wavelength, nuclear physics, and quantum mechanics. This subject consists of many questions in the exam every year, hence, solving the previous year's questions (PYQs) becomes essential for the candidates. Therefore, the JEE Main Session 2 Modern Physics Previous Year Questions 2025 has been provided here for the candidates. Solving PYQs introduces students to the question pattern, the difficulty level, and recurring questions that can improve students' problem-solving skills.
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JEE Main Session 2 Modern Physics Previous Year Questions 2025
Q.1. The energy band gap of semiconducting material to produce violet (wavelength = 4000 A) LED is___________ eV. (Round off to the nearest integer). (JEE MAIN 2022)
Correct Answer: 3
Q.2. A proton and an α-particle are accelerated from rest by 2 V and 4 V potentials, respectively. The ratio of their de-Broglie wavelength is: ( JEE MAIN 2023)
Correct Answer: 4:1
Q.3. Hydrogen ions and singly ionized helium atoms are accelerated from rest through the same potential difference. The ratio of final speeds of hydrogen and helium ions is close to (JEE MAIN 2020)
Correct Answer: 2:1
Q.4. An electron & a photon have the same energy E. Find the ratio of the de Broglie wavelength of an electron to the wavelength of the photon. Given the mass of an electron is m & speed of light is C.
Correct answer: 1/C(E/2m)12
Q.5. The graph of stopping potential V versus the reciprocal of wavelength obtained is shown in the figure in a photoelectric effect experiment. As the intensity of incident radiation is increased. (JEE MAIN 2020)
Correct Answer: The graph does not change.
Q.6. The work Functions of Aluminium and Gold are 4.1eV and 5.1eV respectively. The ratio of the slope of the stopping potential versus frequency plot for Gold to Aluminium is:
(JEE MAIN 2023)
Correct Answer: 1
Q.7. The kinetic energy of an emitted electron is E when the light incident on the metal has wavelength λ. To double the kinetic energy, the incident light must have wavelength: (JEE MAIN 2022)
Correct Answer: hcλ/Eλ+hc
Q.8. When a metal surface is illuminated by light of wavelength A, the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ, the stopping potential is 2V. The threshold wavelength for this surface is: (JEE MAIN 2024)
Correct Answer: 9λ
Q.9. In a photoelectric effect experiment, a light of 1.5 times the threshold frequency falls on the surface of photosensitive material. Now, if the frequency is halved and intensity is doubled, the number of photoelectrons emitted will be: (JEE MAIN 2024)
Correct Answer: 0
Q.10. The light of two different frequencies whose photons have energies of 3.8 eV and 1.4 eV, respectively, illuminate a metallic surface whose work function is 0.6 eV successively. The ratio of maximum speeds of emitted electrons for the two frequencies respectively will be: (JEE MAIN 2022)
Correct Answer: 2:1
Q.11. Number N of the particles deflected in Rutherford's scattering experiment vanes with the angle of deflection Ө. Then, the graph between the two is best represented by (JEE MAIN 2024)
Correct Answer: 1/Ө^2
Q.12. A particle and a carbon 12 atom have the same kinetic energy, K. The ratio of their de-Broglie wavelength (λ: λc12 )is: (JEE MAIN 2024)
Correct Answer: 3:1
Q.13. The de Broglie wavelengths for an electron and a photon are λe & λp, respectively. For the same kinetic energy of electron and photon. Which of the following presents the correct relation between the de Broglie wavelengths of two (JEE MAIN 2022)
Correct Answer: λp∝ λe2
Q14. The particle's kinetic energy is E, and its De-Broglie wavelength is λ. On increasing its △E by Eit's new De-Broglie wavelength becomes λ /2. Then △E is: (JEE MAIN 2020)
Correct Answer: 3E
Q.15. A particle of mass m moves in a circular orbit in a central potential field U(r) = 1/2kr2.If Bohr's quantization conditions are applied, radii of possible orbitals and energy levels vary with quantum number n (JEE MAIN 2019)
Correct Answer: rn∝n2, En∝1/n2
Q.16. A He+ ion is in its first excited state. Its ionization energy is: (JEE MAIN 2019)
Correct Answer: 13.60eV
Q.17. Consider an electron in a hydrogen atom, revolving in its second excited state (having a radius of 4.65 Å). The de-Broglie wavelength of this electron is : (JEE MAIN 2019)
Correct Answer: 9.7Å
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