SSC Maths Part 2 Answer Key 2025: Maharashtra State Board of Secondary & Higher Secondary Education (MSBSHSE) concluded the Class 10 Maths Part 2 Exam today, March 7, 2025. The exam took place for 3 hours from 11 AM to 2 PM. Students who appeared for the SSC Maths Part 2 Exam can check their probable scores with the help of Maharashtra SSC Maths Part 2 Answer Key 2025 provided here. It includes the unofficial answers prepared by the subject experts. Students can also analyse their overall performance by going through the Maharashtra SSC Maths Part 2Â Question Paper Detailed Analysis mentioned below.Â
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SSC Maths Part 2 Answer Key 2025
The Maharashtra SSC Maths Part 2 Exam took place for 60 marks. All questions were compulsory but students were given internal options. Students can cross-check their responses with the unofficial SSC Maths Part 2 Answer Key 2025 and calculate their probable scores.Â
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Question |
Answer |
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Ques 1 (A) (i) Out of the following which is a Pythagorean triplet |
(b) (3,4,5) |
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Ques 1 (A) (ii) â ACB is inscribed angle in a cirele with centre O = 65°, then what in measure of its intercepted arc? |
(d) 130° |
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Ques 1 (A) (iii)Â Distance of point (3, 4) from the origin is |
(c) 5 |
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Ques 1 (A) (iv) If radius of cono in 5 cm and ata perpendicular height is 12 then the slant beight is? |
(c) 13 cm |
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Ques 1 (B) (i) In the following figure triangle ABC, B - D - C and BD = 7, BC = 20. Then find A(ABD)/ A(ABC) |
7/20 |
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Ques 1 (B) (ii) In the following figure MNP - 90°, seg NQ 1 seg MP, MQ - 9, QP=4, find NQ |
6 unit |
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Ques 1 (B) (iii) Angle made by a line with the poritive direction of X-axis is 30°. Find slope of that line. |
1/â3 |
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Ques 1 (B) (iv) In cyclic quadrilateral triangle BCD â A - 100. then find mâ C |
80° |
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Ques 2 (A) (i)Â The radius of a circle with centre P is 10cm. If chord AB the circle subtende a right angle at P. Find area of minor sector using the following activity. |
78.5 sq cm |
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Ques 2 (A) (ii)Â In the following figure chord MN and chord IS internect ot point D. If RD - 15, DS - 4, MD - 8, find DN by complete the following activity. |
7.5 unit |
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Ques 2 (B) (i)Â In triangle ANC, DE II BC. DB - 5.4 cm. AD - 1.8 cm, EC - 7.2 cm. Then find AE |
AE=2.4 cm |
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Ques 2 (B) (ii) In the figure given below, find RS and PS using the given information |
RS = 6 unit, PS = 6â3 unit |
Maharashtra SSC Maths Part 2 Question Paper Analysis 2025
The table below shows the detailed analysis of the Maharashtra SSC Maths Part 2 Question Paper Analysis.Â
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Particulars |
Details |
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Overall Difficulty Level of SSC Maths Part 2 Question Paper |
Moderate |
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Difficulty level of Section A |
Easy to Moderate |
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Difficulty level of Section B |
Easy to Moderate |
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Difficulty level of Section C |
Moderate |
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Difficulty level of Section D |
Moderate |
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Was the paper time consuming? |
A little time consuming |
It is important to note that the Maharashtra SSC Maths Part 2 Answer Key 2025 and Question Paper is only for the analysis purposes. Candidates can use it only to get an idea of their performance.Â