JEE Main Shift 2 Answer Key 1 February 2024

JEE Main Shift 2 Answer Key 1 February 2024: As scheduled, the National Tesing Agency (NTA) concludes the JEE Main 2024 Session 1 Exam 2024 today, Feb 1, 2024. The Feb 1 Shift 2 JEE Main exam was held from 3 PM to 6 PM. 

Candidates who attended the Feb 1 Shift 2 exam can check the JEE Main Shift 2 answer key 1 February 2024 once updated. As per the previous years' trend, candidates can expect NTA to release the provisional JEE Main 2024 answer key by first week of February 2024.

Also, Feb 1 Shift 2 candidates can access the JEE Main Shift 2 Question Paper 1 February 2024 and JEE Main Shift 2 Question Paper Analysis 1 February 2024 which will be soon updated.

Also Read: JEE Main Shift 2 Question Paper 1 February 2024

JEE Main Shift 2 Answer Key 1 February 2024: Download Link

Candidates can access the JEE Main Feb 1 Shift 2 unofficial answer key 2024 PDF link from the table below once available.

Memory Based JEE Main Shift 2 Answer Key 1 February 2024

Candidates can find the memory based JEE Main Shift 2 Answer Key 1 February 2024 given below.

Q1. In an isobaric work done by gas is 200 J. Adiabatic constant for the gas is 1.4 then finds the heat supply to the gas during the process.

1. 700 J
2. 725 J
3. 650 J
4. 900 J

Ans. A

Q2. Two trains run on North-South parallel tracks. Train A moves with velocity 20 m/s towards North and train B moves with velocity 30 m/s towards South. Then find the velocity of train B with respect to train A.

1. 70 m/s
2. 75 m/s
3. 50 m/s
4. 65 m/s

Ans. C

Q3. A source produced electromagnetic wave of frequency 60 MHz Find wavelength of this wave in air.

1. 5m
2. 7.5m
3. 8m
4. 10m

Ans. A

Q4. In the given circuit, galvanometer has 20 resistance. Find ratio of charge stored in 4µF and 6 µF capacitors.

1. 4/9
2. 9/4
3. ⅔
4. ½

Ans. D

Q5. If a bulb of 40W is producing a light of wavelength λ = 4000Å. Then find the number of photons emitted by the bulb per second.

1. 0.803 x 10^{20}
2. 0.403 x 10^{20}
3. 0.503 x 10^{20}
4. 0.803 x 10^{10}

Ans. A

Q6. A disc of mass M and radius R, is rolling with velocity of center of mass v. If it starts moving upwards on an inclined plane, then find the height achieved by the disc before coming to rest.

1. 3v^{2}/4g
2. 4g/3v^{2}
3. 5v^{2}/4g
4. 3v^{2}/5g

Ans. A

Q7. Two factors, \\vec{F_{1}}=6\hat{1}+3\hat{j}+\hat{k}N, \vec{F_{2}}=2\hat{i}+\hat{j}+3\hat{k}\overline{r} are acting on a particle of mass 4 kg. Then find the acceleration of the particle.

1. \sqrt{6}m/s^{2}
2. \sqrt{8}m/s^{2}
3. \sqrt{3}m/s^{2}
4. 6 m/s²

Ans. A

Q8. Find the ratio of electric flux passing through bigger cube to smaller cube in the given situation. 3Q and 2Q charges are placed on the center of the surface on respective cubes.

1. 2/7
2. 7/2
3. 5/2
4. 3/2

Ans. B

Q9. In the figure shown, find the ratio of tensions in the strings, T1 T2

1. 1/4
2. 1/2
3. 1/3
4. 4

Ans. D

Q10. Let a and ẞ the roots of equation px^{2}+qx-r=0, where P\ne0. If p, q, r be the consecutive term of non constant GP and the value of (\alpha-\beta)^{2}is:

1. 80/9
2. 78/7
3. 80/6
4. 82/5

Ans. A

Q11. If the mirror image of the point P(3,4,9) in the Line x-⅓ = y+½ = z-2/1 =  is (α, β, γ) then find (\alpha+\beta+\gamma) is:

1. 54/7
2. 59/9
3. 50/7
4. 52/3

Ans. A

Q12. Let the system of equation x + 2y+3z = 5,2x + 3y + z = 9, 4x + 3y + z = u have infinite number of solution. Then 2u is equal to.

1. 17
2. 19
3. 15
4. 18

Ans. A

The JEE Main Shift 2 Answer Key 1 February 2024 will be prepared by collecting the memory-based questions collected from the candidates who attended the exam. Hence, the answer key might not contain answers to all the questions.

Candidates are advised to use this answer key only for their personal reference. Also, the unofficial JEE Main Shift 2 Answer Key for Feb 1 might contain a few errors/mistakes. Visit the official website of the National Testing Agency (NTA) for more information.

Also Read: JEE Main Shift 2 Question Paper Analysis 1 February 2024